Question

C语言编程，用指针实现两个字符串首位连接的函数strcat(s,t)

用指针实现两个字符串首尾连接的函数strcat(s,t) C语言编程

Answer 1

int strcat(char *s , char *t)
{
int length;
int i=0;
len = strlen( s ) ;
while(t[i]!='\0' )
{
s[length+i] = t[i] ;
i++;
}

s[length+i] = t[i] ;
return 0 ;
}

Answer 2

char* strcat(char* s,char* t)
{
if ( s == NULL || t == NULL)
{
/*exception handling*/
return NULL;
}
int i = 0,j = 0;
while( *(s + i++) );
while(*(s + i++) = *(t + j++));
*(s+i) = '\0';
return s;
}

Answer 3

题目描述不清~

Answer 4

#include <stdio.h>
int strlen( char *s )
{
int slen , i ;
i = 0 ;
while( s[i] )
i ++ ;
slen = i ;
return slen ;
}
int strcat(char *s , char *t)
{
int slen , tlen , i , j ;
slen = strlen( s ) ;
tlen = strlen( t ) ;
for( i = slen , j = 0 ; j < tlen ; j ++ )
{
s[i+j] = t[j] ;
}
s[i+j] = '\0' ;
return 0 ;
}
int main( )
{
char str1[15] = "abcdefg" , str2[15] = "hijklmn" ;
printf( "%s %s\n" , str1 , str2 ) ;
strcat( str1 , str2 ) ;
printf( "%s %s\n" , str1 , str2 ) ;
return 0 ;
}