Question

c# array的问题 怎么找出相同的个数

int[][] lottoNumbers = { new int [] {4, 7, 19, 23, 28, 36}, new int [] {14, 18, 26, 34, 38, 45}, new int [] {8, 10, 11, 19, 28, 30}, new int [] {15, 17, 19, 24, 43, 44}, new int [] {10, 27, 29, 30, 32, 41}, new int [] {9, 13, 26, 32, 37, 43}, new int [] {1, 3, 25, 27, 35, 41}, new int [] {7, 9, 17, 26, 28, 44}, new int [] {17, 18, 20, 28, 33, 38} };int[] drawnNumbers = new int[] { 44, 9, 17, 43, 26, 7, 28, 19 };（这个前6个是winning numbers 后面两个是supplementary numbers）这个就是检测是否中奖没得功能怎么可以做出像图里那样？？

Answer 1

用循环啊。

for(int k=0; k<lottoNumbers.Length; k++)
{
    int[] oneLotto = lottoNumbers[k];
    int foundWinning = 0, foundSupple = 0;
    for(int i=0; i<6; i++)
    {
        foreach(int num in oneLotto)
        {
            if (drawnNumbers[i]==num)
                foundWinning++;
        }
    }
    for(int i=6; i<drawnNumbers.Length; i++)
    {
        foreach(int num in oneLotto)
        {
            if (drawnNumbers[i]==num)
                foundSupple++;
        }
    }
    Console.WriteLine(string.Format("found {0} winning number/s and {1} supplementary numbers/s in Game {2}", foundWinning, foundSupple,k));
}

Answer 2

int[] supplementary=new int[]{drawnNumbers[6],drawnNumbers[7]};
for(int i=0;i<lottoNumbers.Length;i++)
{
    var distinct=lottoNumbers[i].Distinct();
    int total=distinct.Intersect(drawnNumbers).Count();
    int supple=distinct.Intersect(supplementary).Count();
    Console.WriteLine("found {0} winning number/s and {1} supplementary numbers/s in Game {2}", total - supple, supple, i);
}
Console.ReadKey();