1个回答
展开全部
设二次函数y=ax2+bx+c
0=36a-6b+c.......................................1
4=c....................................................2
0=4a+2b+c........................................3
2带入1,3得
18a-3b+2=0..........................4
2a+b+2=0.............................5
5X3+4得
24a+8=0 a=-1/3
b=-4/3
c=4
0=36a-6b+c.......................................1
4=c....................................................2
0=4a+2b+c........................................3
2带入1,3得
18a-3b+2=0..........................4
2a+b+2=0.............................5
5X3+4得
24a+8=0 a=-1/3
b=-4/3
c=4
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询