Question

java从键盘读入10个整数,并对它们进行排序,按由大到小的顺序从控制台输出

Answer 1

请考虑使用快速排序
例如：
public class QuickSort {

private static int[] input = { 3, 5, 3, 76, 45, 23, 7, 44, 25, 54 };

private static void exchange(int from, int to) {
int temp = input[from];
input[from] = input[to];
input[to] = temp;
}

private static int partition(int p, int r) {
int x = input[r];
int i = p - 1;
for (int j = p; j < r; j++) {
if (input[j] <= x) {
i++;
exchange(i, j);
}
}
exchange(i + 1, r);
return i + 1;
}

private static void quickSort(int p, int r) {
if (p < r) {
int q = partition(p, r);
quickSort(p, q - 1);
quickSort(q + 1, r);
}
}

private static void printResult() {
for (int i = 0; i < input.length; i++) {
System.out.println("Index : " + i + "; Value = " + input[i]);
}
}

// nlgn
public static void main(String[] args) {
quickSort(0, input.length - 1);
printResult();
}
}

Answer 2

public class Test {

public static void main(String[] args) {
while (true) {
BufferedReader br = new BufferedReader(
new InputStreamReader(System.in));
System.out.println("请输入你要排序的数字，用逗号分隔：");
String s = "";
try {
s = br.readLine();
//此处可以验证输入的是否符合要求，略
String[] newstr = s.split(",");

int[] aa=new int[newstr.length];
int k=0;
for(String s1:newstr)
{
aa[k]=Integer.parseInt(s1);
k++;
}

Arrays.sort(aa);
for(int s2:aa)
{
System.out.println(s2);
}

} catch (IOException e) {
System.out.println("程序出错：" + e.getMessage());
}
}
}
}

Answer 3

先使用循环用Scanner接收值存储在数组里面 然后 把每个值取出来做判断 if（a〉b）temp=a；a=b；b=temp；（需要用嵌套循环）

Answer 4

同学，要厚道，你怎么能没分呢