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y=(x²-1)(x²-2)(x²-3)
所以，y'=(x²-1)'(x²-2)(x²-3)+(x²-1)(x²-2)'(x²-3)+(x²-1)(x²-2)(x²-3)'
=2x·(x²-2)(x²-3)+2x·(x²-1)(x²-3)+2x·(x²-1)(x²-2)
=2x·[(x²-2)(x²-3)+(x²-1)(x²-3)+(x²-1)(x²-2)]
所以，y'=(x²-1)'(x²-2)(x²-3)+(x²-1)(x²-2)'(x²-3)+(x²-1)(x²-2)(x²-3)'
=2x·(x²-2)(x²-3)+2x·(x²-1)(x²-3)+2x·(x²-1)(x²-2)
=2x·[(x²-2)(x²-3)+(x²-1)(x²-3)+(x²-1)(x²-2)]
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