Question

java Integer.parseInt错误

type Exception report

message

description The server encountered an internal error () that prevented it from fulfilling this request.

exception

org.apache.jasper.JasperException: An exception occurred processing JSP page /adoadd.jsp at line 30

27: <%String uname=request.getParameter("uname");
28: String upass=request.getParameter("upass");
29: String uagestr=request.getParameter("uage");
30: int uage=Integer.parseInt("uagestr");
31: String uemail=request.getParameter("uemail");
32: UsersDao ud=new UsersDao();
33: boolean b=ud.addUser(uname,upass,uage,uemail);

Stacktrace:
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:524)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:435)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)

root cause

java.lang.NumberFormatException: For input string: "uagestr"
java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
java.lang.Integer.parseInt(Integer.java:447)
java.lang.Integer.parseInt(Integer.java:497)
org.apache.jsp.adoadd_jsp._jspService(adoadd_jsp.java:88)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:393)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)

note The full stack trace of the root cause is available in the Apache Tomcat/6.0.14 logs.
谢谢5555555555

Answer 1

int uage=Integer.parseInt("uagestr"); string 类型的值 无法转换啊~
int uage=Integer.parseInt(uagestr); 这样写试试
如果这样的话 是调用uagestr 这个的值

Answer 2

27: <%String uname=request.getParameter("uname");
28: String upass=request.getParameter("upass");
29: String uagestr=request.getParameter("uage");
30: int uage=Integer.parseInt("uagestr");
31: String uemail=request.getParameter("uemail");
32: UsersDao ud=new UsersDao();
33: boolean b=ud.addUser(uname,upass,uage,uemail);

第30行改为int uage=Integer.parseInt(uagestr);