Question

微分方程，这个式子怎么化简？答案在下边求过程

Answer 1

简单计算一下即可，答案如图所示

直接用公式法，简单快捷

Answer 2

(x+1)f''(x) +(x+2)f'(x) =0

(x+1)f''(x) =-(x+2)f'(x)
∫df'(x)/f'(x) = -∫(x+2)/(x+1) dx
ln|f'(x)| = -∫[1+1/(x+1) ]dx
= -x -ln|x+1| +C'
f'(x) = [C/(x+1)]. e^(-x)