Question

c++编程：计算：1!+2!+3!+…+n!

Answer 1

#include <iostream.h>
long Fact(int n);
void main ()
{
int n,d;
long b,c;
do
{
cout<<"请输入一个正整数:";
cin>>n;
c=0;
for (d=1;d<=n;d++)
{
b=Fact(d);
c=c+b;
}
cout<<"和为"<<c<<endl;
}while (n<=0);
}
long Fact(int n)
{
int i;
long result=1;
for (i=1;i<=n;i++)
result *=i;
return result;
}

Answer 2

#include <iostream>
using namespace std;
int main()
{
int i,t,sum,n;
while(cin>>n)
{
sum=0;t=1;
for(i=1;i<=n;i++)
{
t*=i;
sum+=t;
}
cout<<sum<<endl;
}
return 0;
}

追问

嗯嗯，谢谢啦~不过，“ t*=i; “是什么意思呀？……谢谢！

Answer 3

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