Question

求解高数题目，写一下过程

求求了求求了求求了

Answer 1

有理化！
分子分母同时乘以 [√(2x+3）+3][√(x+1)+2]
即：
lim [√(2x+3）-3][√(2x+3）+3][√(x+1)+2] / {[√(2x+3）+3][√(x+1)+2] [√(x+1)-2]}
=lim(2x+3-9)[√(x+1)+2] / {[√(2x+3）+3](x+1-4)}
=lim2(x-3)[√(x+1)+2] / {[√(2x+3）+3](x-3)}
=2lim[√(x+1)+2] / [√(2x+3）+3]
=2lim(√4+2）/(√9+3）
=4/3