先化简,再求值:(x^2-2xy+y^2)/(x^2-xy)÷(x/y-y/x),其中x=3-√3,y=√3
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(x^2-2xy+y^2)/(x^2-xy)÷(x/y-y/x)=(x-y)^2/[x(x-y)]÷(x/y-y/x)
=(x-y)/x÷(x^2/xy-y^2/xy)=(x-y)/x÷(x^2-y^2)/(xy)
=(x-y)/x * (xy)/(x^2-y^2)
=(x-y)/x * (xy)/[(x-y)(x+y)]
=y/(x+y)
把x=3-√3,y=√3带入，得 等于 √3/3
=(x-y)/x÷(x^2/xy-y^2/xy)=(x-y)/x÷(x^2-y^2)/(xy)
=(x-y)/x * (xy)/(x^2-y^2)
=(x-y)/x * (xy)/[(x-y)(x+y)]
=y/(x+y)
把x=3-√3,y=√3带入，得 等于 √3/3
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