Question

编写C程序,求1+1/1!+1/2!+1/3!+1/4!+...+1/n!

n的范围是50以内哦

Answer 1

#include<iostream.h>

int jiecheng(int n){
if(n==1) return 1;
else
return n*jiecheng(n-1);
}

void main(){
int n,i;
double sum=0;
cout<<"输入n:"<<endl;
cin>>n;
for(i=1;i<=n;i++){
sum=sum+1.0/jiecheng(i);
}
cout<<sum<<endl;
}