Question

求y=ln(x+1)/(x-1)的反函数！！！要求详细化简过程！！！

Answer 1

(x+1)/(x-1)=e^y
(x+1)/(x-1)-1=e^y-1
2/(x-1)=e^y-1
x-1=2/(e^y-1)
x=(e^y+1)/(e^y-1)
反函数y=(e^x+1)/(e^x-1)

追问

呵呵，看懂啦

Answer 2

e的y次方=(x+1)/(x-1);
e的y次方*（x-1）=x+1;
e的y次方*x-e的y次方=x+1;
(e的y次方-1)*x=1+e的y次方；
x=（1+e的y次方)/(e的y次方-1)；