
(a-b+4ab/a-b)·(a+b-4ab/a+b)^2
2个回答
展开全部
原式=[(a-b)²+4ab]/(a-b)×[(a+b)²-4ab]²/(a+b)²
=(a²+2ab+b²)/(a-b)×(a²-2ab+b²)²/(a+b)²
=(a+b)²/(a-b)×(a-b)^4/(a+b)²
=(a-b)³
=a³-3a²b+3ab²-b³
=(a²+2ab+b²)/(a-b)×(a²-2ab+b²)²/(a+b)²
=(a+b)²/(a-b)×(a-b)^4/(a+b)²
=(a-b)³
=a³-3a²b+3ab²-b³
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询