Question

(2a-1)²(1+2a)²(4a²+1)²怎样计算？？？

Answer 1

(2a-1)²(1+2a)²(4a²+1)²
=[(2a-1)(1+2a)]²(4a²+1)²
=(4a²-1)²(4a²+1)²
=[(4a²-1)(4a²-1)]²
=(16a^4-1)²
再展开就可以了
=256a^8-32a^4+1

Answer 2

靠
你故意的？

Answer 3

=(2a-1)(2a+1)(2a-1)(2a+1)(4a^2+1)^2
=(4a^2-1)^2(4a^2+1)^2
=(4a^2-1)(4a^2+1)(4a^2-1)(4a^2+1)
=(16a^4-1)(16a^4-1)
=(16a^4-1)^2

Answer 4

=(2a-1)²(2a+1)²(4a²+1)²
=[(2a-1)(2a+1)]²(4a²+1)²
=(4a²-1)²(4a²+1)²
=[(4a²-1)(4a²+1)]²
=(16a^4-1)²
=256a^8-32a^4+1

不知道对没你看看

a^4 指的是 a的4次方 我不会打。

Answer 5

(2a-1)²(1+2a)²(4a²+1)²
=(2a-1)²(2a+1)²(4a²+1)²
=(4a²-1)²(4a²+1)²
=(16a4-1)²

Answer 6

=（2a-1）（2a-1）（2a+1）（2a+1）（4a²+1）(4a²+1)
=(4a²-1)(4a²-1) （4a²+1）(4a²+1)
=(16aaaa-1)(16aaaa-1)
=(16aaaa-1)²