Question

java多个输入输出流写在一个方法里，只能执行一个，是么？看下面程序

private Socket s1;
public ClientThread(Socket s1)
{
this.s1=s1;
}
public void run()
{
try{
BufferedReader br=null;
br=new BufferedReader(new InputStreamReader(s1.getInputStream()));
String str=null;
str = br.readLine();
System.out.println(str);
pro=Runtime.getRuntime().exec("cmd /c tasklist");
BufferedReader ar=null;
ar = new BufferedReader(new InputStreamReader(pro.getInputStream()));
String msg = null;
msg = ar.readLine();//问题1，无法读出tasklist信息，只显示执行两字
System.out.println(msg+"执行");
PrintWriter out=null;
out=new PrintWriter(new OutputStreamWriter(s1.getOutputStream()));
out.println(msg);//问题2，无法将msg字符发出去
out.flush();

} catch (IOException e) {
e.printStackTrace();
}
}
这个程序客户端和服务端代码都在这http://tieba.baidu.com/f?kz=1104377355

若以下回答无法解决问题，邀请你更新回答

Answer 1

问题1：不知道；
问题2：应该是out.write(msg);

追问

谢了

追答

没事