比较大小(1)sin194,cos160(2)sin7/4,cos5/3(3)cos(-47、10派),cos(-44/9派)要过程
展开全部
(1)sin194=-sin14=-cos76
cos160=-cos20<-cos76
所以sin194>cos160
(2)sin7/4>0
cosπ>cos5/3>cos(π/2)=>cos5/3<0
所以sin7/4>cos5/3
(3)cos(-47π/10)=cos(-47π/10+4π)=cos(-7π/10)=cos(7π/10)=cos(63π/90)
cos(-44π/9)=cos(-44π/9+4π)=cos(-8π/9)=cos(8π/9)=cos(80π/90)<cos(63π/90)
所以cos(-47π/10)>cos(-44π/9)
cos160=-cos20<-cos76
所以sin194>cos160
(2)sin7/4>0
cosπ>cos5/3>cos(π/2)=>cos5/3<0
所以sin7/4>cos5/3
(3)cos(-47π/10)=cos(-47π/10+4π)=cos(-7π/10)=cos(7π/10)=cos(63π/90)
cos(-44π/9)=cos(-44π/9+4π)=cos(-8π/9)=cos(8π/9)=cos(80π/90)<cos(63π/90)
所以cos(-47π/10)>cos(-44π/9)
本回答被提问者采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询