Question

用因式分解法 (x-1)的平方-2(x-1)=-1 过程 (1+根号2)x的平方=(1-根号2)x

Answer 1

(x-1)² -2(x-1) = - 1
(x-1)²-2(x-1)+1 = 0
(x-1-1)² = 0 用到 A²-2A + 1 = (A-1)²
x=2

(1+√2)x² = (1-√2)x x≠0时，两边同时约去 x
(1+√2)x=(1-√2)
x = (1 - √2)² 或者 x = 0

Answer 2

楼上回答有错误，字数限制直接写
1.(x-1）²-2（x-1）+1=0； (x-1-1)²=0；(x-2)²=0 ； x=2
2.（1+√2）x²-（1-√2）x=0 ；当x≠0时，两边同时约去 x；(1+√2)x=(1-√2)；x =-(1 - √2)² （负的）或 x = 0

Answer 3

(x-1)² -2(x-1) = - 1
(x-1)²-2(x-1)+1 = 0
A²-2A + 1 = (A-1)²
(x-1-1)² = 0
x=2
(1+√2)x² = (1-√2)x
x=0
或者x≠0时，两边约掉X
(1+√2)x = (1-√2)
x=(1-√2)/(1+√2)
x=2√2-3

Answer 4

(x-1)2-2(x-1)=-1
X2-2x+1-2x+2=-1
X2-4x+4=0
(x-2)2=0
X=2
或
(x-1)2-2(x-1)=-1
(x-1-1)2=0
(x-2)2=0
X=2