Question

求矩阵解题

B={1 1 1
-1 1 -1
1 0 2 }
p={ 0 1 0
1 1 1
-1 -1 0}
p^-1={-1 0 -1
1 0 0
0 1 1}
B=PAP^-1
求A矩阵 请求各位高手帮忙，谢谢

Answer 1

B=PAP^-1
变形：P^-1BP=P^-1PAP^-1P
即：P^-1BP=A
用Matlab输入如下：
B=[1 1 1;-1 1 -1;1 0 2]
B =

1 1 1
-1 1 -1
1 0 2

>> P=[0 1 0;1 1 1;-1 -1 0;]

P =

0 1 0
1 1 1
-1 -1 0

>> p1=inv(P)

p1 =

-1 0 -1
1 0 0
0 1 1

>> A=p1*B*P

A =

2 0 -1
0 1 1
0 0 1

Answer 2

B=PAP^-1
则
A=(P^-1)BP
=
{2 0 -1
0 1 1
0 0 1 }

Answer 3

A = P^-1BP = [ 2 0 -1
0 1 1
0 0 1]

Answer 4

P^-1BP=P^-1PAP^-1P
P^-1BP=A
把已知的带进去算就可以了 就是靠一个简单的化简

Answer 5

哪里有A啊

Answer 6

这个真不懂