初一计算题, 要过程。快一点。谢谢
2011-06-14
展开全部
解:原式=[(a+1)/(a+1)-2/(a+1)]^2/(a-1)/(a+1)-[m/(m+n)-n/(m-n)]+2mn/(m^2-n^2)
=(a-1)/(a+1)-[m(m-n)/[(m+n)(m-n)]-n(m+n)/[(m-n)(m+n)]]+2mn/(m^2-n^2)
=(a-1)/(a+1)-1
=(a-1)/(a+1)-(a+1)/(a+1)
=-2/(a+1)
=(a-1)/(a+1)-[m(m-n)/[(m+n)(m-n)]-n(m+n)/[(m-n)(m+n)]]+2mn/(m^2-n^2)
=(a-1)/(a+1)-1
=(a-1)/(a+1)-(a+1)/(a+1)
=-2/(a+1)
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