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1.(2x+1)²-(-2+1)²2.(x+y-3)(x+y+3)3.(x+1)(x²+1)(x∧4+)(x-1)4(3x+1)²...
1.(2x+1)²-(-2+1)²
2.(x+y-3)(x+y+3)
3.(x+1)(x²+1)(x∧4+)(x-1)
4(3x+1)²(3x-1)²
因式分解:
1.a∧4b∧4—c∧4
2a²-b²-c²+2bc 展开
2.(x+y-3)(x+y+3)
3.(x+1)(x²+1)(x∧4+)(x-1)
4(3x+1)²(3x-1)²
因式分解:
1.a∧4b∧4—c∧4
2a²-b²-c²+2bc 展开
1个回答
展开全部
1.(2x+1)²-(-2x+1)²
=(2x+1)²-(2x-1)²
=(2x+1-2x+1)(2x+1+2x-1)
=2*4x
=8x
2.(x+y-3)(x+y+3)
=(x+y)^2-9
=x^2+2xy+y^2-9
3.(x+1)(x²+1)(x^4+1)(x-1)
=(x-1)(x+1)(x²+1)(x^4+1)
=(x²-1)(x²+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1
4(3x+1)²(3x-1)²
=[(3x+1)(3x-1)]^2
=(9x^2-1)^2
=81x^2-18x^2+1
因式分解:
1.a^4b^4—c^4
=(a^2b^2-c^2)(a^2b^2+c^2)
=(ab-c)(ab+c)(a^2b^2+c^2)
2.a²-b²-c²+2bc
=a²-(b²+c²-2bc)
=a²-(b-c)²
=(a-b+c)(a+b-c)
=(2x+1)²-(2x-1)²
=(2x+1-2x+1)(2x+1+2x-1)
=2*4x
=8x
2.(x+y-3)(x+y+3)
=(x+y)^2-9
=x^2+2xy+y^2-9
3.(x+1)(x²+1)(x^4+1)(x-1)
=(x-1)(x+1)(x²+1)(x^4+1)
=(x²-1)(x²+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1
4(3x+1)²(3x-1)²
=[(3x+1)(3x-1)]^2
=(9x^2-1)^2
=81x^2-18x^2+1
因式分解:
1.a^4b^4—c^4
=(a^2b^2-c^2)(a^2b^2+c^2)
=(ab-c)(ab+c)(a^2b^2+c^2)
2.a²-b²-c²+2bc
=a²-(b²+c²-2bc)
=a²-(b-c)²
=(a-b+c)(a+b-c)
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