Question

c# 如何用其他用户启动exe文件?

RT
process.start("d:\\1.exe")
启动以后在任务管理器里面看用户名是当前登录的用户名,

请问如何用电脑里面的其他用户启动exe文件? 需要设置process的哪些参数?

Answer 1

Process process = new Process();
process.StartInfo.UserName = 指定用户名;
string strPWD = 密码;
SecureString password = new SecureString();
foreach (char c in strPWD.ToCharArray())
{
password.AppendChar(c);
}
process.StartInfo.Password = password;
process.StartInfo.WorkingDirectory = AppDomain.CurrentDomain.BaseDirectory;
process.StartInfo.FileName = "xxx.exe";
process.StartInfo.Arguments = "/run /wu";
process.StartInfo.UseShellExecute = false;
process.Start();

Answer 2

process.start("d:\\1.exe",username,password,domain);
username:就是用户
password:密码
domain：用户所在域

Answer 3

System.Diagnostics.Process process = new System.Diagnostics.Process();
process.StartInfo.FileName = @"D:\Program Files\Tencent\QQ\Bin\QQ.exe"; //"输入完整的路径"
process.StartInfo.Arguments = "QQ.exe"; //启动参数
process.Start();