Question

两道简算 ①2001÷2001又2001/2002+1/2003 ②633×210-（5697×28.3+717×569.7）×11/90

我不要求两道都会的，有一道会写就行，当然两道最好，请写下计算过程，谢谢。

Answer 1

2001÷2001又2001/2001
=2001/[(2001×2002+2001)/2002]
=2001/[(2002×2002)/2002]
=2001/2002

633×210-（5697×28.3+717×569.7）×11/90
=633×210-（5697×28.3+71.7×5697）×11/90
=633×210-（28.3+71.7)×5697×11/90
=633×210-100×5697×11/90
=633×210-110×56970/90
=633×210-110×633
=633×100
=63300

追问

额，第一个简算你落了一个“+1/2003”

Answer 2

ewqe