Question

c语言高手请进:帮我指出错误,再好解释一下错误的原因,先谢谢了!

#include "stdio.h"
char b[4]={"morning","industry","beautiful","english"};
void main()
{
int i;
char *x;
x=&b[2];

for(i=0;i<4;i++)
{
puts(x);
x++;
}
}

Answer 1

char b[4]={"morning","industry","beautiful","english"};
此句有误，b是容量为4个字符的数组，不能用来存放字符串，若想存放一组字符串，建议你用2维数组
注：C中没有String类型，只有Char类型

Answer 2

#include "stdio.h"
char *b[4]={"morning","industry","beautiful","english"};
void main()
{
int i;
char *x;

for(i=0;i<4;i++)
{
x=b[i];
puts(x);
}
getchar();
}

*b[4]是四个字符串
b[i]已经代表了每一个字符串的首地址

这样就可以输出
morning
industry
beautiful
english