
化简: [tan(5π)/4+tan(5π)/12]/[1-tan(5π)/12]
1个回答
展开全部
[tan(5π)/4+tan(5π)/12]/[1-tan(5π)/12]
=tan(π/4)+tan(5π)/12]/[1-tan(π/4)tan(5π)/12]
=tan(π/4+5π/12)=tan(2π/3)=-tan(π/3)=-√3
=tan(π/4)+tan(5π)/12]/[1-tan(π/4)tan(5π)/12]
=tan(π/4+5π/12)=tan(2π/3)=-tan(π/3)=-√3
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询