Question

php读取数据库数据怎么显示不出来？？？

<?php
$link_ID = mysql_pconnect('localhost','root','root');
if(mysql_select_db('1000tou',$link_ID)){
//echo "OK";
}else{
echo "NG";
}
$sql = "select * from fwcz ";
$Query_ID = mysql_query($sql);
$Record = mysql_fetch_array($Query_ID);
$num = mysql_num_rows($Query_ID);
echo $Record[0];
echo $Record[1];
echo $Record[2];
echo $Record[3];
echo $Record[4];
echo $Record[5];
echo $Record[6];
?>
这样写得代码 但显示的是

Answer 1

因为你使用的是mysql_fetch_array的方法 输出的话必须使用 echo $Record['字段名'];
比如有一个name字段就是用 echo $Record[''name];
如果要使用 echo $Record[0]的形式 应该使用mysql_fetch_rows()

Answer 2

mysql_pconnect多了个p

追问

也显示不出来啊

Answer 3

<?php
$link_ID = mysql_pconnect('localhost','root','root');
if(mysql_select_db('1000tou',$link_ID)){
//echo "OK";
}else{
echo "NG";
}
$sql = "select * from fwcz ";
$Query_ID = mysql_query($sql);
$num = mysql_num_rows($Query_ID);
while($Record = mysql_fetch_array($Query_ID)){//行
echo $Record[列];
}
?>