
上一个产品 下一个产品 asp页面 增加的按钮该怎么写 谁会?请帮个忙。谢谢。
<%d=request.QueryString("d")ifd<>""thensetrs=conn.execute("select*fromproductwhereid=...
<%
d=request.QueryString("d")
if d<>"" then
set rs=conn.execute("select * from product where id="&d)
if not rs.eof then
tit=rs("tit")
s=rs("sortid")
spic=rs("spic")
p1=rs("p1")
p2=rs("p2")
p3=rs("p3")
p4=rs("p4")
p5=rs("p5")
content=rs("content")
end if
end if
if s<>"" then
set rs1=conn.execute("select * from sort where id="&s)
if not rs1.eof then
select case rs1("page")
case 1
lkid=s
pageid=1
sorttit=rs1("tit")
case 2
sort1id=rs1("s1")
sorttit=rs1("tit")
pageid=2
lkid=rs1("s1")
case 3
sort1id=rs1("s1")
sort2id=rs1("s2")
sorttit=rs1("tit")
pageid=3
lkid=rs1("s1")
end select
end if
closers(rs1)
end if
select case pageid
case 1
plook= "<a href='p.asp?s="&s&"'>"&sorttit&"</a>"
ptit=sorttit&"/"&tit
case 2
set rs=conn.execute("select * from sort where id="&sort1id)
if not rs.eof then
sort1tit=rs("tit")
end if
closers(rs)
plook= "<a href='p.asp?s="&sort1id&"'>"&sort1tit&"></a><a href='p.asp?s="&s&"'>"&sorttit&"</a><a href='#'>"&tit&"</a>"
ptit=sort1tit&"/"&sorttit&""
case 3
set rs=conn.execute("select * from sort where id="&sort1id)
if not rs.eof then
sort1tit=rs("tit")
end if
closers(rs)
set rs=conn.execute("select * from sort where id="&sort2id)
if not rs.eof then
sort2tit=rs("tit")
end if
closers(rs)
ptit=tit&","&sorttit&","&sort2tit&","&sort1tit
plook= "<a href='p.asp?s="&sort1id&"'>"&sort1tit&"></a><a href='p.asp?s="&sort2id&"'>"&sort2tit&"></a><a href='p.asp?s="&s&"'>"&sorttit&"></a><a href='#'>"&tit&"</a>"
end select
%>
<title><%=ptit%>/产品展示/<%=C_title%></title>
<td align="left" class="abouttit">产品展示 <font class="ti">Product Exhibition</font></td>
</tr>
<tr>
<td align="right" style="padding:15px 48px;">
</td>
</tr>
<tr>
<td height="138" align="center" valign="top" style="padding:8px 48px; background:url(img/aboutbg.jpg) bottom repeat-x;"><%=content%></td>
页面基本代码,这样该怎么实现上一个产品与下一个产品链接?帮忙写一下谢谢了。 展开
d=request.QueryString("d")
if d<>"" then
set rs=conn.execute("select * from product where id="&d)
if not rs.eof then
tit=rs("tit")
s=rs("sortid")
spic=rs("spic")
p1=rs("p1")
p2=rs("p2")
p3=rs("p3")
p4=rs("p4")
p5=rs("p5")
content=rs("content")
end if
end if
if s<>"" then
set rs1=conn.execute("select * from sort where id="&s)
if not rs1.eof then
select case rs1("page")
case 1
lkid=s
pageid=1
sorttit=rs1("tit")
case 2
sort1id=rs1("s1")
sorttit=rs1("tit")
pageid=2
lkid=rs1("s1")
case 3
sort1id=rs1("s1")
sort2id=rs1("s2")
sorttit=rs1("tit")
pageid=3
lkid=rs1("s1")
end select
end if
closers(rs1)
end if
select case pageid
case 1
plook= "<a href='p.asp?s="&s&"'>"&sorttit&"</a>"
ptit=sorttit&"/"&tit
case 2
set rs=conn.execute("select * from sort where id="&sort1id)
if not rs.eof then
sort1tit=rs("tit")
end if
closers(rs)
plook= "<a href='p.asp?s="&sort1id&"'>"&sort1tit&"></a><a href='p.asp?s="&s&"'>"&sorttit&"</a><a href='#'>"&tit&"</a>"
ptit=sort1tit&"/"&sorttit&""
case 3
set rs=conn.execute("select * from sort where id="&sort1id)
if not rs.eof then
sort1tit=rs("tit")
end if
closers(rs)
set rs=conn.execute("select * from sort where id="&sort2id)
if not rs.eof then
sort2tit=rs("tit")
end if
closers(rs)
ptit=tit&","&sorttit&","&sort2tit&","&sort1tit
plook= "<a href='p.asp?s="&sort1id&"'>"&sort1tit&"></a><a href='p.asp?s="&sort2id&"'>"&sort2tit&"></a><a href='p.asp?s="&s&"'>"&sorttit&"></a><a href='#'>"&tit&"</a>"
end select
%>
<title><%=ptit%>/产品展示/<%=C_title%></title>
<td align="left" class="abouttit">产品展示 <font class="ti">Product Exhibition</font></td>
</tr>
<tr>
<td align="right" style="padding:15px 48px;">
</td>
</tr>
<tr>
<td height="138" align="center" valign="top" style="padding:8px 48px; background:url(img/aboutbg.jpg) bottom repeat-x;"><%=content%></td>
页面基本代码,这样该怎么实现上一个产品与下一个产品链接?帮忙写一下谢谢了。 展开
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