Question

题目“阶乘尾数零的个数。N！的末尾有多少个零。”把带有C++语句的部分改成C语言的语法，头文件要stdio.h

#include <iostream>
using namespace std;
int main()
{
int n,c=0;
cout<<"please input n"<<endl;
cin>>n;
while(n!=0)
{
n/=5;
c+=n;
}
cout<<"the number of zero is "<<c<<endl;
return 0;
}

Answer 1

#include <stdio.h>
int main()
{
int n,c=0;
printf("please input n\n");//输出”please input n“到屏幕，\n 表示回车换行
scanf("%d", &n);//从键盘读取一个整数
while(n!=0)
{
n/=5;
c+=n;
}
printf("the number of zero is %d\n", c);//输出"the number of zero is %d\n"到屏幕，其中%d用c的值替换
return 0;
}

Answer 2

#include<stdio.h>
int main()
{
int n,c=0;
printf("please input n\n");
scanf("%d",&n);
while(n!=0)
{
n/=5;
c+=n;
}
printf("the number of zero is %d",c);
printf("\n");
return 0;
}
希望你能满意……

Answer 3

#include <stdio.h>
int main()
{
int n,c=0;
printf("please input n");
sacnf("%d",&n);
while(n!=0)
{
n/=5;
c+=n;
}
printf("the number of zero is %d\n",c);
return 0;
}

Answer 4

n/=5; //这个方法挺好的哈，学习啦。。。