已知X平方/X平方-2=1/1-根号3-根号2,求(1/1-X-1/1+X)÷(X/X平方-1+X) 速度啊 ！！！
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x^2/(x^2-2)=1/(1-√3-√2)取倒数
(x^2-2)/x^2=1-√3-√2
1-2/x^2=1-√3-√2
-2/x^2=-√3-√2
2/x^2=√3+√2
x^2=2/(√3+√2)
[1/(1-x)-1/(1+x)]÷[x/(x^2-1)+x]
=[(1+x)/(1-x)(1+x)-(1-x)/(1-x)(1+x)]÷[x/(x^2-1)+x]
=[(1+x-1+x)/(1-x)(1+x)]÷[x/(x^2-1)+x]
=[2x/(1-x^2)]÷[x/(x^2-1)+x]
=[2/(1-x^2)]÷[1/(x^2-1)+1]
=[2/(1-x^2)]÷[(1+x^2-1)/(x^2-1)]
=[2/(1-x^2)]÷[x^2/(x^2-1)]
=2/(1-x^2)*(x^2-1)/x^2
=-2/(x^2-1)*(x^2-1)/x^2
=-2/x^2
=-2/[2/(√3+√2)]
=-2*(√3+√2)/2
=-√3-√2
(x^2-2)/x^2=1-√3-√2
1-2/x^2=1-√3-√2
-2/x^2=-√3-√2
2/x^2=√3+√2
x^2=2/(√3+√2)
[1/(1-x)-1/(1+x)]÷[x/(x^2-1)+x]
=[(1+x)/(1-x)(1+x)-(1-x)/(1-x)(1+x)]÷[x/(x^2-1)+x]
=[(1+x-1+x)/(1-x)(1+x)]÷[x/(x^2-1)+x]
=[2x/(1-x^2)]÷[x/(x^2-1)+x]
=[2/(1-x^2)]÷[1/(x^2-1)+1]
=[2/(1-x^2)]÷[(1+x^2-1)/(x^2-1)]
=[2/(1-x^2)]÷[x^2/(x^2-1)]
=2/(1-x^2)*(x^2-1)/x^2
=-2/(x^2-1)*(x^2-1)/x^2
=-2/x^2
=-2/[2/(√3+√2)]
=-2*(√3+√2)/2
=-√3-√2
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