Question

设计一个c语言程序,完成下列和式计算 1+1/2-1/3+1/4-1/5+1/6-1/7+1/8-1/9+1/10

Answer 1

#include<stdio.h>
void main()
{
int M;
M=1+1/2-1/3+1/4-1/5+1/6-1/7+1/8-1/9+1/10;
printf("%d",M);
}

Answer 2

float j=1;
for(i=2;i<=10;i++)
{
if(i%2)
j-=(float)1/(float)i;
else
j+=(float)1/(float)i;
}

Answer 3

double sum=1;
int fuhao = 1;
for (int i=2;i<=10;i++)
{
sum += 1/i*fuhao ;
fuhao *= -1;
}