Question

java TXT空行解决

以下是我读取一个TXT文件中'S'开头的单词，但我现在遇到是这个TXT文件中一但有空行程序就结束了！因为我用BufferedReader br = new BufferedReader(fr);去逐行读取了！怎么才能解决呢？
String fname = "c:\\1.txt";
File f = new File(fname);
try {
FileReader fr = new FileReader(f);
BufferedReader br = new BufferedReader(fr);
String s = br.readLine();
//Pattern p = Pattern.compile("\\W(S.*?)([0-9])\\W");
Pattern p = Pattern.compile("\\W(S.([0-9])*?)\\W");
Matcher m = p.matcher(s);
while (s!=null){
while (m.find()) {
System.out.println(m.group(1));
//System.out.println(s);
//m.find()!=true;
db2NameString=m.group(1).substring(1, 8);
db2Name=Integer.parseInt(m.group(1).substring(1, 8));

} s= br.readLine();
}

br.close();// 关闭缓冲读入流及文件读入流的连接.

} catch (FileNotFoundException e1) {
System.err.println("File not found: " + fname);
} catch (IOException e2) {
e2.printStackTrace();
}

Answer 1

String fname = "c:\\1.txt";
File f = new File(fname);
try {
FileReader fr = new FileReader(f);
BufferedReader br = new BufferedReader(fr);
while (br.ready()) {
String s = br.readLine();
Pattern p = Pattern.compile("\\W(S.([0-9])*?)\\W");
Matcher m = p.matcher(s);
// System.out.println(s);
while (m.find()) {
System.out.println(m.group(1));
// System.out.println(s);
// m.find()!=true;
db2NameString=m.group(1).substring(1, 8);
db2Name=Integer.parseInt(m.group(1).substring(1, 8));

}
}

br.close();// 关闭缓冲读入流及文件读入流的连接.

} catch (FileNotFoundException e1) {
System.err.println("File not found: " + fname);
} catch (IOException e2) {
e2.printStackTrace();
}