初二数学 要过程 函数y=kx+b的如右图,则方程kx+b等于0的解为?不等式kx+b>0的解集为?

函数y=kx+b的如右图,则方程kx+b等于0的解为?不等式kx+b>0的解集为?不等式kx+b-3>0的解集为?... 函数y=kx+b的如右图,则方程kx+b等于0的解为?不等式kx+b>0的解集为?不等式kx+b-3>0的解集为? 展开
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kx+b等于0 y=0 所以就是函数与x轴的交点 1 所以解为1
kx+b>0 即函数在x轴的上面 所以 x<1
同理 kx+b<0的解集为 x>1
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解:把A(1,0),B(0,3)带入y=kx+b
0=k+b
3=b
解得k= -3
b=3
所以y= -3x+3
① 令y=0 ② -3x+3>0 ③ -3x+3-3>0
-3x+3=0 x>1 -3x>0
x=1 所以原不等式的集解为x>1 x<0
所以原方程的解为x=1 所以原不等式的解集为x<0
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