已知x／x²－x＋1＝2，求x²／(x²)²﹢x²﹢1的值
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(x^2-x+1)/x
=x^2/x-x/x+1/x
=x+1/x-1
=1/2
x+1/x=3/2
[(x^2)^2+x^2+1]/x^2
=(x^4+x^2+1)/x^2
=x^2+1/x^2+1
=x^2+2*x*(1/x)+(1/x)^2-1
=(x+1/x)^2-1
=(3/2)^2-1
=5/4
x^2/[(x^2)^2+x^2+1]=4/5
=x^2/x-x/x+1/x
=x+1/x-1
=1/2
x+1/x=3/2
[(x^2)^2+x^2+1]/x^2
=(x^4+x^2+1)/x^2
=x^2+1/x^2+1
=x^2+2*x*(1/x)+(1/x)^2-1
=(x+1/x)^2-1
=(3/2)^2-1
=5/4
x^2/[(x^2)^2+x^2+1]=4/5
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x／x²－x＋1＝2
(x²-x+1)/x=1/2
x-1+1/x=1/2
x+1/x=-1/2
[(x²)²﹢x²﹢1]/x²
=x²+1+1/x²
=(x+1/x)²-1
=1/4-1
=-3/4
∴x²／[(x²)²﹢x²﹢1]=-4/3
(x²-x+1)/x=1/2
x-1+1/x=1/2
x+1/x=-1/2
[(x²)²﹢x²﹢1]/x²
=x²+1+1/x²
=(x+1/x)²-1
=1/4-1
=-3/4
∴x²／[(x²)²﹢x²﹢1]=-4/3
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x／x²－x＋1＝2
(x²－x＋1)/x＝1/2
x+1/x=3/2
[(x²)²﹢x²﹢1]/x^2
=x^2+1/x^2+1
=(x+1/x)^2-1
=(3/2)^2-1
=5/4
x²／(x²)²﹢x²﹢1=1/(5/4)=4/5
(x²－x＋1)/x＝1/2
x+1/x=3/2
[(x²)²﹢x²﹢1]/x^2
=x^2+1/x^2+1
=(x+1/x)^2-1
=(3/2)^2-1
=5/4
x²／(x²)²﹢x²﹢1=1/(5/4)=4/5
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