Question

#include ＜stdio.h＞ void main() { int x,y; for(y=1,x=1; y<=20;y++) { if(x>=8) break;

if(x%2==1){ x+=5; continue ; }

x-=3;

}

printf(“x=%d, y=%d\n”,x ,y);

就运行结果

Answer 1

1 #include<stdio.h>
2 void main()
3 {
4 int x,y;
5 for(y=1,x=1; y<=20;y++)
6 { if(x>=8) break;
7 if(x%2==1)
8 {
9 x+=5;
10 continue ;
11 }
12 x-=3;
13 }
14 printf("x=%d,y=%d\n",x,y);
15 }
16

结果
x=8, y=4

Answer 2

x没赋初值，把sum=sum+x;放到y=y+1;的后面就可以了.
另外y=y+1可以写成y+=t;
#include<stdio.h>
void main()
{
int sum,x,t,y,z,n;
sum=0,z=1,y=2;
for(n=1,n<=20,n++)
{
sum=sum + x;
x= y / z;
t= z;
z = y;
y +=t;
}
printf("%d\n",sum);
}

Answer 3

x=8,y=4

Answer 4

x=8,y=4