Question

编写程序，求1-3+5-7……-99+101的值 谢谢

用C语言

Answer 1

#include<stdio.h>
main()
{
int i,j,k=0,p=0,temp;
for(i=1;i<=101;i=i+4)
k+=i;
for(j=3;j<100;j=j+4)
p+=j;
temp=k-p;
printf("%d",temp);
}

Answer 2

#include <stdio.h>
main()
{
int i,flag=1,j,sum=0;
for(i=1;i<=101;i=i+2)
{
if(flag%2)
j=i;
else
j=-1*i;
printf("%d\n",j);
sum+=j;
flag++;
}
printf("1-3+....-99+101=%d\n",sum);
return 0;
}

Answer 3

#include<stdio.h>
#include<stdlib.h>

#define MAX 101

void main()
{
int i, j, n, sum=0;

for (i=0;i<=MAX/2;i++) {
printf ("%d", 2*i+1);
if(i%2==0) {
printf("-");
n = 2*i+1;
}
else {
printf("+");
n = (-1)*(2*i+1);
}
sum += n;
}
printf ("\b=%d\n", sum);
}

Answer 4

int main()
{ int s=0,j=1,i;
for(i=1;i<=101;i+=2)
{j=-j;
s+=-j*i;/*求1-3+5-7……-99+101的值*/
}
printf("1-3+....-99+101=%d\n",s);
return 0;
}

Answer 5

#include "stdio.h"

void main()
{
int k = 1;
int num = 1;
int i = 1;

for (i = 1; k <= 101; i++)
{
printf("%d",k);
k = k+2;
if (i%2 == 1)
{
printf("-");
num = num - k;
}
else
{
printf("+");
num = num + k;
}
}
printf(" = %d",num);
}