Question

未报告的异常 java.io.IOException；必须对其进行捕捉或声明以便抛出

import java.lang.*;
import java.io.*;

class exponent
{
public static void main(String args[])
{
ObjectInputStream jin = new ObjectInputStream(System.in);
double tsampled = Double.Double(args[1]).doubleValue();
while(tsampled!=Double.NaN)
{
System.out.print(Double.valueOf(tsampled));
System.out.print(Math.getExponent(Double.valueOf(tsampled)));
tsampled = jin.readDouble();
}
}
};

//F:\doc\source codes\java\exponent>javac exponent.java
//exponent.java:9: 未报告的异常 java.io.IOException；必须对其进行捕捉或声明以便抛出
// ObjectInputStream jin = new ObjectInputStream(System.in);
// ^
//exponent.java:10: 未报告的异常 java.io.IOException；必须对其进行捕捉或声明以便抛出
// double tsampled = jin.readDouble();
// ^
//2 错误
//
//F:\doc\source codes\java\exponent>

顺便问一下，System.in怎么用？

Answer 1

public static void main(String args[]) throws IOException { //你这里写错了
ObjectInputStream jin = new ObjectInputStream(System.in);
double tsampled = Double.valueOf(args[0]); //你这里方法写错了，而且貌似数组下标也用错了
while (tsampled != Double.NaN) {
System.out.print(Double.valueOf(tsampled));
System.out.print(Math.getExponent(Double.valueOf(tsampled)));
tsampled = jin.readDouble();
}
}

仅检查语法，没有做其他检查

这是根据你的需求写的代码（我理解中的你的需求）：

public static void main(String args[]) throws IOException {
BufferedReader reader = new BufferedReader(new InputStreamReader(
System.in));
String line = reader.readLine();

while (line != null) {

double tsampled = Double.valueOf(line);
System.out.println(tsampled);
System.out.println(Math.getExponent(tsampled));
line = reader.readLine();
}
}

Answer 2

将代码放到try catch块中

Answer 3

加一段try就好了，因为JAVA程序必须对可能发生的异常进行处理
修改如下：
public int readFile(String sFileName)
{
BufferedReader br = new BufferedReader(new FileReader(sFileName));
try{
String sRead = br.readLine();
int iCount = Integer.parseInt(sRead);
br.close();
}
catch(Exception e){
e.printStacktrace();
}

return iCount;
}

Answer 4

貌似你用记事本写的代码？
木有错误提示？