Question

奥数计算题

1. 231除以231又232分之231

2. 123454321乘11111分之1

3. 1328乘1239减739乘661减739乘667

快求解

Answer 1

1 231/(231又231/232)
=231/((231+231*232)/232)
=231*232/(231+231*232)
=231*232/(231*233)
=232/233
2 123454321*(1/11111)
=(111110000+12344321)*(1/11111)
=(111110000+11111000+1111100+111110+11111)*(1/11111)
=10000+1000+100+10+1
=11111
3 1328*1239-739*661-739*667
=1328*1239-739*1328
=1328*500
=664000
:)

Answer 2

1.231又232分之231=(231×232+231)/232
这就算化简了
2.你要是知道123454321=11111×11111这事就好办了
3.1328×1239-739×661-739×667=1328×1239-(739×661+739×667)=1328×1239-739×(661+667)
=1328×1239-739×1328=1328×(1239-739)=1328×500=66400
就是一提取公因数嘛~