解关于x的方程：x^2-2x+1-k(x^2-1)=0 再帮我解下这个
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x^2 - 2x + 1 - k(x-1)(x+1) = (x-1)^2 - k(x-1)(x+1)
=(x-1)(x-1-kx-k)
=(x-1)((1-k)x - (1+k))
= 0
x = 1 or (1-k)x - (1+k) = 0 ==> k =/= 1, x = (1+k)/(1-k)
k =/= 1, x =1, or (1+k)/(1-k)
k = 1, x = 1
=(x-1)(x-1-kx-k)
=(x-1)((1-k)x - (1+k))
= 0
x = 1 or (1-k)x - (1+k) = 0 ==> k =/= 1, x = (1+k)/(1-k)
k =/= 1, x =1, or (1+k)/(1-k)
k = 1, x = 1
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