Question

一道数学题：计算（a+2)²（a-2）²（a²+4）² 求详细过程、答案

Answer 1

（a+2)²（a-2）²（a²+4）²
=[（a+2)（a-2）]²（a²+4）²
=﹙a²-4﹚²（a²+4）²
=[﹙a²-4﹚（a²+4）]²
=（a四次方-16）²
=a八次方－32a四次方＋256

Answer 2

解：原式=(a+2)(a-2)(a+2)(a-2)(a²+4)(a²+4)
=(a²-4)(a²-4)(a²+4)(a²+4)
=（a四次方-16）²

Answer 3

= [(a+2)(a-2)]^2 *(a^2+4)^2
=(a^2 - 4)^2 * (a^2 + 4)^2
=[(a^2-4)(a^2+4)]^2
=(a^4 - 16)^2
= a^8 - 32a^4 + 256

Answer 4

（a+2)²（a-2）²（a²+4）²
=[（a+2)(a-2)]²(a²+4)²
=(a²-4)²(a²+4)²
=(a4-16)²
=a8-32a4+256

Answer 5

（a+2)²（a-2）²（a²+4）²
=[(a+2)(a-2)]²(a²+4)²
=(a²-4)²(a²+4)²
=[(a²-4)(a²+4)]²
=(a^4-16)²