Question

用MATLAB 画出圆环面

Answer 1

r=1; % small radius of the small circle

d=2; % distance of small circle to the center

phi=(0:pi/16:2*pi)'; % points of small circle

alpha=(0:pi/32:2*pi)'; % points of big circle

X2=[d+r*cos(phi) r*sin(phi)]; % small circle

Z=X2(:,2)';Z=Z(ones(1,length(alpha)),:);

X=Z;Y=Z;

for i=1:length(alpha)

X(i,:)=cos(alpha(i))*X2(:,1)';Y(i,:)=sin(alpha(i))*X2(:,1)';

end

surf(X,Y,Z)

axis equal

Answer 2

本视频展示如何用matlab绘制散圆状态图，可用于相关科研数据绘图！

Answer 3

你画呀