Question

C语言制作简单的通讯录

从键盘上输入姓名，电话号码，住址
可把每个人的信息全部输出
按姓名查找，将查询信息输出
添加一条通讯录信息，并输出看是否添加成功
信息删除，修改功能
《用结构体，函数实现》]
TY~
问题是我们没有用过链表，而且，老师要求用结晶构体和函数实现。。。。所以，我才感觉棘手哈
PS：网上的相关源代码上基本上全是链表

Answer 1

主要是链表的操作，直接定义个结构体和指针的运用。

Answer 2

/*编程建立一通讯簿，存放有姓名、电话号码、住址，然后对通信簿进行查找、添加、修改及删除。*/
#include<stdio.h>
struct person
{
char name[8];
char tel[15];
char addr[50];
};

char filename[20];
FILE *fp;

void creat();
void output();
void search();
void append();
void modify();
void delete();

main()
{
int m;

creat();
while(1)
{
printf("\n\n添加，请按1");
printf("\n查找，请按2");
printf("\n修改，请按3");
printf("\n删除，请按4");
printf("\n输出，请按5");
printf("\n退出，请按0\n");
scanf("%d",&m);
if(m>=0&&m<=5)
{
switch(m)
{
case 1: append();
break;
case 2: search();
break;
case 3: modify();
break;
case 4: delete();
break;
case 5: output();
break;
case 0: exit();
}
printf("\n\n操作完毕，请再次选择！");
}
else
printf("\n\n选择错误，请再次选择！");
}
}

void creat()
{
struct person one;
long s1;

printf("\n请输入通讯簿名：");
scanf("%s",filename);
if((fp=fopen(filename,"w"))==NULL)
{
printf("\n不能建立通讯簿！");
exit();
}
fprintf(fp,"%-10s%-20s%-50s\n","姓名","电话号码","住址");
printf("\n请输入姓名、电话号码及住址（以0结束）\n");
scanf("%s",one.name);
while(strcmp(one.name,"0"))
{
scanf("%s%s",one.tel,one.addr);
fprintf(fp,"%-10s%-20s%-50s\n",one.name,one.tel,one.addr);
scanf("%s",one.name);
}
fclose(fp);
}

void output()
{
struct person one;

if((fp=fopen(filename,"r"))==NULL)
{
printf("\n不能打开通讯簿！");
exit();
}
printf("\n\n%20s\n","通 讯 簿");
while(!feof(fp))
{
fscanf(fp,"%s%s%s\n",one.name,one.tel,one.addr);
printf("%-10s%-20s%-50s",one.name,one.tel,one.addr);
}
fclose(fp);
}

void append()
{
struct person one;

if((fp=fopen(filename,"a"))==NULL)
{
printf("\n不能打开通讯簿！");
exit();
}
printf("\n请输入添加的姓名、电话号码及住址\n");
scanf("%s%s%s",one.name,one.tel,one.addr);
fprintf(fp,"%-10s%-20s%-50s\n",one.name,one.tel,one.addr);
fclose(fp);
}

void search()
{
int k=0;
char namekey[8];
struct person one;

printf("\n请输入姓名:");
scanf("%s",namekey);

if((fp=fopen(filename,"rb"))==NULL)
{
printf("\n不能打开通讯簿！");
exit();
}
while(!feof(fp))
{
fscanf(fp,"%s%s%s\n",one.name,one.tel,one.addr);
if(!strcmp(namekey,one.name))
{
printf("\n\n已查到，记录为：");
printf("\n%-10s%-18s%-50s",one.name,one.tel,one.addr);
k=1;
}
}
if(!k)
printf("\n\n对不起，通讯簿中没有此人的记录。");
fclose(fp);
}

void modify()
{
int m,k=0;
long offset;
char namekey[8];
struct person one;

printf("\n请输入姓名:");
scanf("%s",namekey);

if((fp=fopen(filename,"r+"))==NULL)
{
printf("\n不能打开通讯簿！");
exit();
}
while(!feof(fp))
{
offset=ftell(fp);
fscanf(fp,"%s%s%s\n",one.name,one.tel,one.addr);
if(!strcmp(namekey,one.name))
{
k=1;
break;
}
}
if(k)
{
printf("\n已查到，记录为：");
printf("\n%-10s%-18s%-50s",one.name,one.tel,one.addr);
printf("\n请输入新姓名、电话号码及住址：");
scanf("%s%s%s",one.name,one.tel,one.addr);
fseek(fp,offset,SEEK_SET);
printf("%ld",ftell(fp));
fprintf(fp,"%-10s%-20s%-50s\n",one.name,one.tel,one.addr);
}
else
printf("\n对不起，通讯簿中没有此人的记录。");
fclose(fp);
}

void delete()
{
int m,k=0,flag;
long offset1,offset2;
char namekey[8], valid[4];
struct person one;

printf("\n请输入姓名:");
scanf("%s",namekey);
if((fp=fopen(filename,"r+"))==NULL)
{
printf("\n不能打开通讯簿！");
exit();
}
while(!feof(fp))
{
offset1=ftell(fp);
fscanf(fp,"%s%s%s\n",one.name,one.tel,one.addr);
if(!strcmp(namekey,one.name))
{
k=1;
break;
}
}
if(k)
{
printf("\n已查到，记录为");
printf("\n%-10s%-18s%-50s",one.name,one.tel,one.addr);
printf("\n确实要删除,按1；不删除，按0：");
scanf("%d",&m);
if(m)
{
fseek(fp,offset1,SEEK_SET);
fprintf(fp,"%-10s%-20s%-50s\n","","","");
}
}
else
printf("\n对不起，通讯簿中没有此人的记录。");
fclose(fp);
}

Answer 3

用一单连表就搞定了，很简单的啊