Question

在一定条件下，能够说明可逆反应3A+B=2C达到平衡状态

A、的消耗速率等于B的生成速率
B、A、B、C的分子数之比为3:1:2
C、单位时间内消耗3molA，同时生成1molB2molC
D、单位时间内消耗3molA，同时生成2molC

要具体解析，谢谢~

Answer 1

选C
从化学平衡的定义来看，判断一个可逆反应是否达到平衡有两个标志：一是正逆反应速率相等，二是各组分的浓度不再变化。
A错，A的消耗速率对应正反应，B的生成速率对应逆反应，但它们的比应该是系数之比3:1才说明正逆反应速率相等；
B错，A、B、C的分子数之比为3:1:2，仅凭这点我们无法得知正逆反应速率是否相等、浓度是否还在变化；
C对，单位时间内消耗3molA，同时必生成2molC，这是正反应，但同时生成1molB就是逆反应了，且符合系数比，说明正逆反应速率已相等；
D错，单位时间内消耗3molA，同时生成2molC恒成立，因为只是说了正反应。

Answer 2

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