Question

甲乙两车分别从A、B两地出发，相

甲 乙 两车分别从A、B两地出发相向而行. 出发时.甲、乙的速度比是5∶4, 相遇后,甲的速度减少20% ,乙的速度提高 20% ,这样,当甲到达B地时.乙离A地还有10. 那么A.B两地相距多少千米?

Answer 1

AB两地为X千米；甲、乙速度比是5 ：4，那么相遇时甲行了5/9 X千米，乙行了4/9 X千米；
后面是甲行了4/9X /（5-5×20%）=乙行了（5/9X-10） /（4+4×20%）。
设：AB两地相距为X千米。 解： （4/9X)/(5-5×20%）=（5/9X-10）/（4+4×20%）
(4/9X)/4=(5/9X-10)/4.8 对角相乘得： 19.2/9 X=20/9 X-40 两边同乘以9得：
19.2X=20X-360 0.8X=360 X=450（千米）
答：AB两地相距450千米。

Answer 2

5/9-5/9*20%=4/9
4/9+4/9*20%=8/15
4/9:8/15=5:6
10/(6/11-5/11)=110
相距110千米

Answer 3

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