Question

解分式方程x+1/(4x-6)=(a²+3a+1)/2a 急~

Answer 1

方程应该是x+1/"("4x-6")"=(a*a+3a+1)/2a 吧!
展开得到x+1/(4x+6)=a/2+3/2+1/2a,就把右边3/2移左边左边,把X配成4x-6形式:(4x-6)/4+1/(4x-6)=a/2+1/2a,=>(4x-6)/2+2/(4x-6)=a+1/a
所以(4x-6)/2=a或1/a,x=(2a+6)/4或(2/a+6)/4
7月S7

Answer 2

方程应该是x+1/"("4x-6")"=(a*a+3a+1)/2a 吧!
展开得到x+1/(4x+6)=a/2+3/2+1/2a,就把右边3/2移左边左边,把X配成4x-6形式:(4x-6)/4+1/(4x-6)=a/2+1/2a,=>(4x-6)/2+2/(4x-6)=a+1/a
所以(4x-6)/2=a或1/a,x=(2a+6)/4或(2/a+6)/4
7月H2

Answer 3

x+1/(4x-6)=(a²+3a+1)/2a
2ax(4x-6)+2a=(a²+3a+1)(4x+6)
4ax²-(2a²+12a+2)x+(3a²+10a+3)=0
[2ax-(3a+1)]*[2x-(a+3)]=0
x1=(3a+1)/(2a)
x2=(a+3)/2