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计算:(x-3)/(x^2+3x+2)·x^2-4/x^2-4x+3
2个回答
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[(x-3)/(x^2+3x+2)]·[(x^2-4)/(x^2-4x+3)]
={(x-3))/[(x+1)(x+2)]} × {(x-2)(x+2)/[(x-1)(x-3)]}
=(x-2)/(x²-1) (注:分子/分母)
={(x-3))/[(x+1)(x+2)]} × {(x-2)(x+2)/[(x-1)(x-3)]}
=(x-2)/(x²-1) (注:分子/分母)
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