(x4+y4)2-(2x2y2)2分解因式,求详细答案
1个回答
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(x4+y4)2-(2x2y2)2
=(x^4+y^4+2x²y²)(x^4+y^4-2x²y²)
=(x²+y²)²(x²-y²)²
=(x²+y²)²(x+y)²(x-y)²
=(x^4+y^4+2x²y²)(x^4+y^4-2x²y²)
=(x²+y²)²(x²-y²)²
=(x²+y²)²(x+y)²(x-y)²
追问
(x^4+y^4+2x²y²)(x^4+y^4-2x²y²)到(x²+y²)²(x²-y²)²是怎么回事
追答
x^4+y^4+2x²y²=(x²)²+2x²y²+(y²)²=(x²+y²)² 完全平方式
(x²-y²)²
=[(x+y)(x-y)]² (ab)²=a²b²
=(x+y)²(x-y)²
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