Question

因式分解x的四次方+3x的平方乘y的平方+4y的四次方

Answer 1

原式=x^4+4x²y²+4y^4-x²y²
=(x²+2y²)²-(xy)²
=(x²+xy+2y²)(x²-xy+2y²)

Answer 2

= x^4 + 4x^2 * y^2 + 4y^4 - x^2 * y^2
= (x^2 + 2y^2)^2 - (xy)^2
=(x^2 -xy + 2y^2)(x^2 + xy + 2y^2)