(x+y-2)(x+y-2xy)+(xy-1)² 这个怎么因式分解呀。。。急 急 急 急 急
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(x+y-2xy)(x+y-2)+(1-xy)²
=(x+y)²-2(1+xy)(x+y)+4xy+1-2xy+x²y²
=(x+y)²-2(1+xy)(x+y)+(1+xy)²
=(x+y)²-(1+xy)(x+y)-(1+xy)(x+y)+(1+xy)²
=(x+y)(x+y-1-xy)-(1+xy)(x+y-1-xy)
=(x+y-1-xy)(x+y-1-xy)
=(x+y-1-xy)²
=(x+y)²-2(1+xy)(x+y)+4xy+1-2xy+x²y²
=(x+y)²-2(1+xy)(x+y)+(1+xy)²
=(x+y)²-(1+xy)(x+y)-(1+xy)(x+y)+(1+xy)²
=(x+y)(x+y-1-xy)-(1+xy)(x+y-1-xy)
=(x+y-1-xy)(x+y-1-xy)
=(x+y-1-xy)²
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