为什么sin(x+π/4)的平方等于cos(x-π/4)的平方?
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sin(x+π/4)=sinxcosπ/4+cosxsinπ/4=√2/2(sinx+cosx)
cos(x-π/4)=cosxcosπ/4+sinxsinπ/4=√2/2(sinx+cosx)
这种根据正余弦公式比较容易理解
cos(x-π/4)=cosxcosπ/4+sinxsinπ/4=√2/2(sinx+cosx)
这种根据正余弦公式比较容易理解
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{sin(x+π/4)}^2
={sin[(x-π/4)+π/2]}^2
={sin(x-π/4)cos(π/2)+cos(x-π/4)sin(π/2)}^2
={sin(x-π/4)·0+cos(x-π/4)·1}^2
={cos(x-π/4}^2
={sin[(x-π/4)+π/2]}^2
={sin(x-π/4)cos(π/2)+cos(x-π/4)sin(π/2)}^2
={sin(x-π/4)·0+cos(x-π/4)·1}^2
={cos(x-π/4}^2
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