Question

解方程：x-2分之x+x-7分之x-9=x-1分之x+1+x-6分之x-8

Answer 1

x=4

结果正在上传   ……

Answer 2

x-2分之x+x-7分之x-9=x-1分之x+1+x-6分之x-8
(x-2+2/x-2)+(x-7-2/x-7)=(x-1+2/x-1)+(x-6-2/x-6)
1+(2/x-2)+1-(2/x-7)=1+(2/x-1)+1-(2/x-6)
(1/x-2)-(1/x-7)=(1/x-1)-(1/x-6)
(1/x-2)+(1/x-6)=(1/x-7)+(1/x-1)
x-6+x-2/(x-2)(x-6)=x-1+x-7/(x-1)(x-7)
2x-8/(x-2)(x-6)=2x-8/(x-1)(x-7)
2x-8=0
x=4

Answer 3

请加括号

追问

没有括号

追答

是这样吗？
x/(x-2)+x/(x-7)-9=x/(x-1)+1+x/(x-6)-8

追问

是：x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)

追答

x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)
(x-2+2)/(x-2)+(x-7-2)/(x-7)=(x-1+2)/(x-1)+(x-6-2)/(x-6)
1+2/(x-2)+1-2/(x-7)=1+2/(x-1)+1-2/(x-6)
1/(x-2)+1-1/(x-7)=1/(x-1)-1/(x-6)
[x-7-(x-2)]/[(x-1)(x-2)]=[x-6-(x-1)][(x-6)(x-7)]
-5/[(x-1)(x-2)]=-5[(x-6)(x-7)]
(x-1)(x-2)=(x-6)(x-7)
x^2-3x+2=x^2-13x+42
10x=40
x=4
经验证，x=4不是增根

Answer 4

你表述的不够明确，但是很简单，就是不知道哪个是分母哪个是分子。。。不好意思了