Question

C语言实现多个文本合并

在C语言中如何实现多个文本文件的合并
我想到的思路就是把要合并的文件放在一个文件夹内,然后运行程序后
在这个文件夹内的所有文件的内容将会容进一个文件里

Answer 1

#include "stdio.h"
#include "stdlib.h"
#include "string.h"

long filesize(FILE *stream); /* 求文件的长度 */

int main()
{
int i;
char inf1,inf2,outf; /* 用户输入的文件路径 */
FILE *in1, *in2, *out; /*in1,in2为待合并的文件，out为合并后的文件 */
unsigned long in1fileLength,in2fileLength;
char *buf1, *buf2;

printf("------------------------------------------------\n");
printf("> Please input parameter:\n");
printf("> test <InputFileName1><InputFileName2> <OutputFileName>:\n");
printf("------------------------------------------------\n");

printf("These are the command-line arguments passed to"
" main:\n\n");

scanf("%s",inf1); /* 用户输入待合并的文件1 */
if ((in1 = fopen(inf1, "rb")) == NULL)
{
printf("Cannot open input file1.\n");
exit(1);
}
else
printf("file1 is opened,please input the file2\n");
scanf("%s",inf2); /* 待合并文件2 */
if ((in2 = fopen(inf2, "rb")) == NULL)
{
printf("Cannot open input file2.\n");
exit(1);
}
else
printf("file2 is opened,please input the loctation after united\n");
scanf("%s",outf); /* 经过合并操作后存放的路径 */
if ((out = fopen(outf, "wb"))== NULL)
{
printf("Cannot open output file.\n");
exit(1);
}

in1fileLength = filesize(in1); /* 文件1的长度 */
in2fileLength = filesize(in2); /* 文件2的长度 */

buf1 = (char *)malloc(in1fileLength); /* 读出放入缓冲区中 */
buf2 = (char *)malloc(in2fileLength);

fread(buf1,in1fileLength, 1, in1);
fread(buf2,in2fileLength, 1, in2);

fwrite(buf1, in1fileLength, 1, out); /* 写入out文件中 */
fwrite(buf2, in2fileLength, 1, out);
printf("unit is successful!,and the loctation is %s",outf);

fclose(in1); /* 关闭文件 */
fclose(in2);
fclose(out);

return 1;
}

long filesize(FILE *stream) /* 求文件长度的函数 */
{
long curpos1, curpos2,length;

fopen(stream,"rb");
curpos1= ftell(stream);
fseek(stream, 0L, SEEK_END);
curpos2= ftell(stream);
length=curpos2-curpos1;
fseek(stream, curpos1, SEEK_SET);
return length;
fclose(stream);
}